<｜begin▁of▁sentence｜>### Instruction:
Given a graph with the edge set [(1, 2), (1, 3), (2, 3), (3, 4), (4, 5)], can you determine the maximum locally (k,l)-connected subgraph where k=2 and l=1 using NetworkX? Additionally, identify if the resulting subgraph is the same as the original.
### Response:
import networkx as nx

# Create a graph
G = nx.Graph()
G.add_edges_from([(1, 2), (1, 3), (2, 3), (3, 4), (4, 5)])

# Find the maximum locally (k,l)-connected subgraph
k = 2  # The maximum length of paths to consider
l = 1  # The number of edge-disjoint paths

# Use the low_memory option if necessary
low_memory = False

# Use the same_as_graph option to check if the original graph is (k,l)-connected
H, is_same = nx.kl_connected_subgraph(G, k, l, low_memory=low_memory, same_as_graph=True)

# Print the result
def nodes_edges(g):
    return list(g.nodes()), list(g.edges())

print('Nodes:', nodes_edges(H)[0])
print('Edges:', nodes_edges(H)[1])
print('Is the same graph:', is_same)
<|EOT|>
