<｜begin▁of▁sentence｜>### Instruction:
Given a graph with nodes labeled 'node0', 'node1', and 'node2', and edges connecting 'node0' to 'node1', 'node1' to 'node2', and 'node0' to 'node2', each with their own unique label, can you determine if the graph is locally (2,1)-connected, meaning for each edge in the graph there is at least 1 edge-disjoint path of length at most 2 joining the endpoints of the edge?
### Response:
import networkx as nx

# Create a graph
G = nx.Graph()

# Add nodes
G.add_nodes_from([(0, {'label': 'node0'}), (1, {'label': 'node1'}), (2, {'label': 'node2'})])

# Add edges
G.add_edges_from([(0, 1, {'label': 'edge0'}), (1, 2, {'label': 'edge1'}), (0, 2, {'label': 'edge2'})])

# Define k and l
k = 2
l = 1

# Check if the graph is locally (k,l)-connected
connected = nx.is_kl_connected(G, k, l)

print('Is the graph locally (k,l)-connected?', connected)
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