<｜begin▁of▁sentence｜>### Instruction:
Given a circle centered at (4, 4) with a radius of 2 and a source point at (1, 1), can you use the ShapeDrawer.intersection_point method in igraph's CircleDrawer class to calculate the intersection point of a line drawn from the source point to the center of the circle?
### Response:
from igraph.drawing.shapes import CircleDrawer

# Assume we have circle centered at (4, 4) with radius 2
# And a source point (1, 1)
center_x = 4
center_y = 4
source_x = 1
source_y = 1
radius = 2  # Since it's a circle, width equals the radius

# Determining the intersection point
intersection = CircleDrawer.intersection_point(center_x, center_y, source_x, source_y, radius)
print(f'Intersection Point: {intersection}')
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